Jawaban:
jawaban ada dibawah ini:
Penjelasan dengan langkah-langkah:
1.
segita kecil:
[tex]y = \sqrt{ {10}^{2} - {9}^{2} } \\ y = \sqrt{100 - 81} \\ y = \sqrt{19} [/tex]
panjang AR =
[tex]8 \sqrt{19} [/tex]
panjang x:
[tex]10 + x = \sqrt{ {(8 + \sqrt{19}) }^{2} + {27}^{2} } \\ 10 + x = \sqrt{(64 + 19) + 729} \\ 10 + x = \sqrt{812} \\ 10 + x = 2 \sqrt{203} \\ x = 2 \sqrt{203} - 10[/tex]
2.
segitiga kecil:
[tex]x = \sqrt{ {14}^{2} - {6}^{2} } \\ x = \sqrt{196 - 36} \\ x = \sqrt{160} \\ x = \sqrt{16 \times 10} \\ x = 4 \sqrt{10} [/tex]
panjang Y:
[tex]y = \sqrt{ {(20 + 14)}^{2} - {(15 + 4 \sqrt{10} )}^{2} } \\ y = \sqrt{ {34}^{2} - {(15 + \sqrt{160}) }^{2} } \\ y = \sqrt{1156 - (225 + 160)} \\ y = \sqrt{1156 - 385} \\ y = \sqrt{771} [/tex]
semoga membantu!!
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